Menu
From The Math Page:
$$sin θ = \frac{opposite}{hypotenuse}$$ $$csc θ = \frac{hypotenuse}{opposite}$$ $$cos θ = \frac{adjacent}{hypotenuse}$$ $$sec θ = \frac{hypotenuse}{adjacent}$$ $$tan θ = \frac{opposite}{adjacent}$$ $$cot θ = \frac{adjacent}{opposite}$$
Pythagorean Identities
$$sin^2 θ + cos^2 θ = 1$$ $$1 + tan^2 θ = sec^2 θ$$ $$1 + cot^2 θ = csc^2 θ $$
A general example to help you recognize patterns and spot the information you're looking for
Show: $$sec^2 x + csc^2 x = sec^2 x csc^2 x$$ Solution: The problem means that we are to write the left-hand side, and then show, through substitutions and algebra, that we can transform it to look like the right hand side. We begin: $$sec^2 x + csc^2 x = \frac{1}{cos^2 x} + \frac{1}{sin^2 x}$$ $$sec^2 x + csc^2 x = \frac{sin^2 x + cos^2 x}{cos^2 x sin^2 X}$$ $$sec^2 x + csc^2 x = \frac{1}{cos^2 x sin^2 x}$$ $$sec^2 x + csc^2 x = \frac{1}{cos^2 x} * \frac{1}{sin^2 x}$$ $$sec^2 x + csc^2 x = sec^2 x csc^2 x$$
Trigonometric functions are important in the study of triangles and modeling periodic phenomena, among many other applications.
Watch a Khan Academy Video »
Length: 9:22
Watch a Khan Academy Video »
Length: 8:21
Watch a Khan Academy Video »
Length: 9:55
Watch a Khan Academy Video »
Length: 6:34
Watch a Khan Academy Video »
Length: 9:09